AB is a chord of a circle with Centre O .at B a tangent PB is drawn such that its length is 24 cm the distance of P from the centre is 26 CM if the chord AB is 16 cm .find its distance from the centre
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According to question
Length of Chord ab = 16 Cm
Length of tangent bp = 24 Cm
and op = 26 Cm
Thus
In the figure
if we draw a perpendicular from o on tangent bp to point y
we can say that
by = yp
Thus
yp = bp / 2
= 24/2
= 12 Cm
Thus in triangle oyp
op^2 = oy^2 + yp^2
Thus
oy^2 = 26^2 - 12^2
oy = 23 Cm
Length of Chord ab = 16 Cm
Length of tangent bp = 24 Cm
and op = 26 Cm
Thus
In the figure
if we draw a perpendicular from o on tangent bp to point y
we can say that
by = yp
Thus
yp = bp / 2
= 24/2
= 12 Cm
Thus in triangle oyp
op^2 = oy^2 + yp^2
Thus
oy^2 = 26^2 - 12^2
oy = 23 Cm
rudra80:
pls explain y
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