AB is a chord of circle substending an angle 90 degrees at the center O of the circle If the radius of the circle is 6cm the area of minor segment is
Answers
Answered by
2
Answer:
area of minor sector = area of chord - area of triangle
area of chord = (Ф /360) x πr^2 = 9π
area of triangle = 1/2 x b x h = 1/2 x 6 x 6 = 18
so ans is 9π - 18
pls add to brainliest
Step-by-step explanation:
Similar questions