AB is a chord of circle with center O. If OP perpendicularAB and extended OP meets the circle at C and AB=6cm,PC=2cm,then find the length of the radius.
Answers
Given -
AB = 6 cm, OD = 4 cm and O is the center of the circle.
AB is a chord and OD is perpendicular to AB.
OA = Radius = ?
It is clear from the figure that AD = DB =1/2 of AD
=1/2 x 6
AD = 3 cm
Now. using Pythagoras Theorem,
(Hypotenuse)2 = (Base)? + (Perpendicular)
(OA)² = (AD)² + (OD)²
(OA)² = (3)²+ (4)²
(OA)² = 9 + 16
(OA)² = 25
taking square root,
OA = v25
OA = 5 cm
So, the radius of the circle is 5 cm.
Answer:
The radius is .
Step-by-step explanation:
It is given that:
AB is a chord of circle with center O. If OP is perpendicular to AB and extended OP meets the circle at C.
We need to determine the radius.
If OP is perpendicular to AB, then
The theorem says that "the products of the lengths of the line segments on each chord are equal".
If be diameter if circle, then
According to theorem
Diameter
Radius
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