Question

AB is a chord of length 24 cm of a circle of radius 13 cm. The tangents at A and B intersect

Answer 1

Answer:

HEY MATE HERE'S YOUR ANSWER

Step-by-step explanation:

AB=24 CM, OA=OB=13 CM. O IS THE CENTRE OF THE CIRCLE.

DRAW OD PERPENDICULAR TO AB, AD= BD= 12 CM.

NOW AC AND BC ARE TANGENTS.

IN TRIANGLE AOD, OD= 5 CM (BY PYTHAGORAS THEOREM).

NOW, IN TRIANGLE AOD AND TRIANGLE CAD,

<OAD= 90-<AOD  AND  < ACD= 90-<OAD.

THUS, <OAD= <ACD.

<ADO=<ADC=90.

BY AA SIMILARITY,

TRIANGLE AOD  ~ TRIANGLE CAD.

RATIO OF SIDES:AC/OA = AD/OD THUS ,

AC/13 = 12/5

AC= (12  X  13)/5

=31.2 CM.

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