AB is a chord of radius r. If p is any point on the circle such that angle APB is a right angle, then find the length AB
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Answer:
The line AC passes through O. So it is a diameter of the circle.
∴∠ABC is an angle inscribed in a semicircle.
∴∠ABC=90O.
Now ∠ABC+∠ACB+∠BAC=180O ...(sum of the { angles of a Δ=180O)
⇒50O+90O+∠BAC=180O
⇒∠BAC=40O
Again, AT is a tangent to the circle at A.
∴∠CAT=90O
⇒∠BAT+∠CAB=90O
⇒∠BAT+40o=90O
⇒∠BAT=50O.
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