Question

AB is a chord of the circle with Centre O and radius 13 cm if OM, AB and OM equal to 5 cm find the length of the chord AB.

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Answer 1

Answer:

maths

Step-by-step explanation:

Perpendicular drawn from centre of a circle to chord bisects the chord.

AC=BC=12cm

And ∠OCB=90

∘

Thus, triangle OCB is a right angled triangle

OB=13cm.

Therefore by Pythagoras theorem

OB

2

=OC

2

+BC

2

OC

2

=OB

2

−BC

2

OC=

13

2

−12

2

OC=26m

option C will be the answer.

Answer 2

Answer:

Option c is the correct answer.