Question

AB is a demeter of the ____circle​

Answer 1

Answer:

 

∠ACB=90°  (Angle subtended on semi-circle)

In, △ACB,

∠CAB=180°-(∠ACB+∠CBA)

=180°-(90°+70°)

=20°

Now,

∠DCA+∠ACB+∠BAC+∠DAC=180°   [Sum of opp. anglesof cyclic quadrilateralis supplementary.]

∠DCA+90°+20°+30°=180°

∠ACD=180°-40°

∠ACD=40°

Hence, 40° is the correct answer.

Step-by-step explanation:

Answer 2

Answer:

40 is the answer

Step-by-step explanation:

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