Question

AB is a diameter in the adjacent figure. If ∟A = 30˚, then find ∟B?

Answer 1

Answer:

∠BOC+∠OBC+∠BCO=180°

∠BOC+60° +60 °

=180°

∠BOC=180 ° −120°

∠BOC=60 °

Hence, this is the answer.

Step-by-step explanation:

given that,

∠ACO=30°

Then, we know that

∠ACB=90°

(angle formed in semi circle is a right angle)

Now,

∠ACB=∠ACO+∠BCO

90° =30° +∠BCO∠BCO=60°

In ΔAOC

We know that.

AO=CO (radius of circle)

Then,

∠OAC=∠ACO

∠OAC=30°

ln ΔBOC

We know that.

BO=CO (radius of circle)

Then,

∠OBC=∠BCO

∠OBC=60°

Again,In ΔBOC

We know that,

∠BOC+∠OBC+∠BCO=180°

∠BOC+60° +60 °

=180°

∠BOC=180 ° −120°

∠BOC=60 °

Hence, this is the answer