AB is a diameter of a circle .AH and BK are perpendiculars from A and B respectively to the tangent at P .Prove that AH + BK= AB
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According to question
Let O be the center of the circle and join O to P
Thus OP = radius of the circle = r
we are given that AB = diamete
So AB / 2 = Radius = r = OP
Also OP = AH = BK
So
AB / 2 = AH
AB = 2 AH
AB = AH + BK
Hence Proved
Let O be the center of the circle and join O to P
Thus OP = radius of the circle = r
we are given that AB = diamete
So AB / 2 = Radius = r = OP
Also OP = AH = BK
So
AB / 2 = AH
AB = 2 AH
AB = AH + BK
Hence Proved
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