AB is a diameter of a circle and C is any point on the circle.Show that the area of △ABC is maximum,when it is isosceles.
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Clearly,
-> sin ( 2 x theta ) is maximum at theta = 45°
Hence, we prove the triangle is isosceles for maximum area !
Note : We used the fact that the diameter subtends a right angle at the arcs !
Clearly,
-> sin ( 2 x theta ) is maximum at theta = 45°
Hence, we prove the triangle is isosceles for maximum area !
Note : We used the fact that the diameter subtends a right angle at the arcs !
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