AB is a diameter of a circle. C is a point on the tangent drawn at A . If AB = 8 cm and AC = 6 cm , then the length of BC is
A) 10 cm B) 14 cm C) 5 cm D) 7 cm
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On the basis of question we draw a figure of a circle with centre O ,
Given that , AB = 8 cm and AC = 6 cm
AB ⊥ AC
∴ ∠BAC = 90°
From ∆ BAC ,
∴ BC = √AB² + AC²
BC = √8² + 6²
BC = √64 + 36 = √100 = 10 cm.
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