Question

AB is a diameter of a circle C ( O, r) . Chord CD is equal to radius DC. If AC and BD

when produced intersect at P. Show that < APB = constant.​

Answer 1

Step-by-step explanation:

In△OCD

OC=OB=CD

∴∠COD=60(Anglesofequilateraltriangle)

AS∠CAD=

2

1

∠COD=

2

1

×60=30

Now∠ADP=∠ADB=90(Angleinsemicircle)

In△ADP

∠ADP+∠DPA+∠DAP=180

⇒90+∠DPA+30=180

⇒∠DPA=180−120=60=∠APB

Hence option (c) is right

answer

hope it's correct and help full

Answer 2

Answer:

your answer is given above

Step-by-step explanation:

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