AB is a diameter of a circle . P is a pt on the semi circle APB . AH and BK r perpendicular from A and B respectively to the tangent at present prove that AH + BK = AB
chandan23:
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Answered by
41
Draw perpendicular from centre O to point P . it is also the radius of the circle .
now,AH = PO and BK = PO
therefore 2PO = AH + BK
but 2PO = AB ( 2 radius = diameter)
so AB = AH + BK
!hope this helpful!
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The figure is as follows
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