AB is a diameter of a circle with centre O and AC is its chord such that angle BAC = 30 DEGREE . If the tangent drawn at C intersects extended AB at D, then show that BC=CD
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FIRST OF ALL!!!!! please don't give wrong sums in this place.....and in this answer I am going to prove you that ur sum is ABS. WRONG!!!!!
angle(ACB)=90.....ANGLE IN A SEMICIRCLE
angle(CBD)=120....SUM OF THE OPP. INTERIOR ANGLES..
if cb=CD....
then,
angle(CBD)=angle(CDB)
OR...THERE WILL BE TWO OBTUSED ANGLES IN A TRIANGLE..WHICH IS INSANE!!! (120 DEGREE)
SO...PLEASE FROM NEXT TIME..DONT GIVE WRONG SUMS
angle(ACB)=90.....ANGLE IN A SEMICIRCLE
angle(CBD)=120....SUM OF THE OPP. INTERIOR ANGLES..
if cb=CD....
then,
angle(CBD)=angle(CDB)
OR...THERE WILL BE TWO OBTUSED ANGLES IN A TRIANGLE..WHICH IS INSANE!!! (120 DEGREE)
SO...PLEASE FROM NEXT TIME..DONT GIVE WRONG SUMS
EON:
its perfectly right question so please try to solve bc=bd
first of all my friend...notice what u have written in the question. you have written bc=cd, i hope u now understand the difference. ^_^
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