AB is a diameter of a circle with centre O and AT is a tangent. If ∠AOQ = 58°
find ∠ATQ.
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Angle ATQ=61 .... hope it helps !!
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Answer:
Angle ABQ=1/2 angle AOQ
=1/2*58
=29
Angle A =90(AT is a tangent)
angle BAT+angle ABT +angle ATQ=180(angle sum
property of triangle.)
90+29+angle ATQ= 180
angle ATQ=180-119
angle ATQ=61
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