Math, asked by MPP, 1 year ago

AB is a diameter of a circle with centre O and AT is a tangent. If ∠AOQ = 58°
find ∠ATQ.

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Answers

Answered by Anonymous
54
Angle ATQ=61 .... hope it helps !!
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Answered by Anonymous
24

Answer:

Angle ABQ=1/2 angle AOQ

=1/2*58

=29

Angle A =90(AT is a tangent)

angle BAT+angle ABT +angle ATQ=180(angle sum

property of triangle.)

90+29+angle ATQ= 180

angle ATQ=180-119

angle ATQ=61

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