Question

AB is a diameter of a circle, with centre O. If ∠PAB = 55˚, ∠PBQ = 25˚, and ∠ABR = 50˚, find ∠PBA, ∠BPQ and ∠RAB

Answer 1

Answer:

Angle PAB = 55

Angle PBQ = 25

Angle ABR = 50

Thus

Angle PBA + Angle PAB + Angle BPA = 180

55 + 90 +  Angle PBA = 180

      Angle PBA = 180 - 145

                        = 35

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