Question

AB is a diameter of circle. Chord CD is equal to radius OD. AC and BD produced interest at P. Prove that angle APB= 60°

Answer 1

Answer:  see..  ao=bo=co=do(radius) cd is also a radius (given) thus,Δocd is an equilateral triangle so all angles are 60° now.. oa║cd so , ∠oca=60° similiarly, ob║cd so, ∠odb=60°  ∠dcp=180-(60+60)° (linear pair) ⇒60° similiarly, ∠cdp=180-(60+60)° (linear pair)  by angle sum property.. ∠cpd=180-(60+60)° ⇒180-120° ⇒60°  hence proved hope this helps and plzzz mark it the brainliest..

Answer 2

Answer:

Step-by-step explanation:

d is also a radius (given)

thus,Δocd is an equilateral triangle

so all angles are 60°

now..

oa║cd

so , ∠oca=60°

similiarly,

ob║cd

so, ∠odb=60°  ∠dcp=180-(60+60)° (linear pair)

⇒60°

similiarly,

∠cdp=180-(60+60)° (linear pair)  by angle sum property..

∠cpd=180-(60+60)°

⇒180-120°

⇒60°  hence proved

hope this helps and plzzz mark it brainliest