AB is a diameter of semicircle ACB, where C is the
mid-point of arc ACB. Find the ratio of perimeters of
the semicircle and triangle ABC.
(a) (π+2)(√2-1) : 2
(b) (√2 +1) : (√2-1)
(c) √2 : 1
(d) π+2 : 2√2
(e)√2 +2 : 1
Answers
Answered by
0
Step-by-step explanation:
Let O be the centre of the circle. Then, OA=OB=OD=r
Now, OC=r−2
and CD=6
Thus, in △ODC
OC
2
+CD
2
=OD
2
(r−2)
2
+6
2
=r
2
r
2
+4−4r+36=r
2
4r=40
r=10 cm
Area of semicircle =
2
πr
2
=
2
π(10)
2
=50π
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