Question

ab is a diameter of the circle such that angle A is equal to 35 degree and Angle Q is equals to 25 degree find angle pbr​

Answer 1

Answer:

∠PBR =  115°

Step-by-step explanation:

Missing figure of question is attached :

Now in Δ ABQ

∠A + ∠ABQ + ∠Q = 180°

=> 35° + ∠ABQ + 25° = 180°

=> ∠ABQ = 120°

=> ∠ABR + ∠ABQ = 180° straight line

=> ∠ABR + 120° = 180°

=> ∠ABR = 60°

in ΔAPB

AB is diameter => ∠APB = 90°

∠A +  ∠APB + ∠PBA = 180°

=> 35° + 90° + ∠PBA = 180°

=> ∠PBA = 55°

∠PBR = ∠PBA + ∠ABR

=> ∠PBR = 55° + 60°

=> ∠PBR =  115°

Answer 2

Answer: 115°

In triangle ABQ, By angle sum property of a triangle,

<ABQ+<BQA+<QAB=180°

<ABQ+25°+35°=180°

<ABQ+60°=180°

<ABQ=180°-60°

<ABQ=120°

AB is the diameter of the circle.

Therefore, <APB=90° ( angle in a semicircle )

In triangle APB, By angle sum property of the triangle,

<BAP+<APB+<PBA=180°

35°+90°+<PBA=180°

125°+<PBA=180°

<PBA=180°-125°

<PBA=55°

<PBR=<PBA+<ABR

<PBR=55°+60°

<PBR=115°