Math, asked by sohamchakraborty1, 1 year ago

AB is a diametre of the cyclic quadrilateral ABCD, <ABC-65 degree, <DAC-60 degree then <BCD-?

Answers

Answered by Mayank972
0
Its 90° angle in a semicircle is 90°
Answered by Amankasera
0
The angle BCD is 90 because it form by the diameter

sohamchakraborty1: Plzz show the diagram
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