Question

AB is a line segment and line L is its perpendicular bisector. If a point P lies on L,show that P is equidistant from A and B

Answer 1

▪Question:-

AB is a line segment and line L is its perpendicular bisector. If a point P lies on L,show that P is equidistant from A and B

▪Solution:-

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since , AB is a line segment,

L is drawn perpendicular to AB,

A point 'p' lies on line L.

To prove : P is equidistant from A and B.

In ∆AOP and ∆BOP ,

OP = OP ( common side )

∠ POA = ∠ POB

AO = OB

$\therefore$∆AOP$\cong$ ∆BOP (By S.A.S.)

=> AP = BP

Hence,"P" is equidistant from A and B .

Answer 2

Refer to the attachment_

$hope \: it \: helps$