AB is a line segment and line L is its perpendicular bisector if point P lies on L show that equidistant from A and B
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Solution 1:
AB is a line segment and l is its perpendicular bisector. If a point P lies on l. Show that P is equidistant from A and B.
since , AB is a line segment,
L is drawn perpendicular to AB,
A point 'p' lies on line L.
{To\: prove} : P is equidistant from A and B.
{Prove} :-
In ∆AOP and ∆BOP ,
OP = OP ( common side )
\anglePOA = \anglePOB
AO = OB
\therefore ∆AOP \cong ∆BOP (By S.A.S.)
=> AP = BP ( By C.P.C.T. )
Hence , "P" is equidistant from A and B .
solution 2:
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