Question

AB is a line segment and line l is its perpendicular bisector. If a point P lies on l, show that P is equidistant from A and B.


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Answer 1

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$\huge{\underline{\bf{Question:}}}$

AB is a line segment and line l is its perpendicular bisector. If a point P lies on l, show that P is equidistant from A and B.

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$\huge{\underline{\bf{Solution:}}}$

since , AB is a line segment,

L is drawn perpendicular to AB,

A point 'p' lies on line L.

(As shown in diagram in the attachment)

: P is equidistant from A and B.

:-

In ∆AOP and ∆BOP ,

OP = OP ( common side )

POA = POB

AO = OB

∆AOP ∆BOP (By S.A.S.)

=> AP = BP ( By C.P.C.T. )

Hence , "P" is equidistant from A and B .

$\huge{\underline{\boxed{\bf{Proved!}}}}$

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