AB is a line segment and Pis its mid-point. D and
E are points on the same side of AB such that
BAD = Z ABE and Z EPA = Z DPB
(see Fig. 7.22). Show that
(i) ADAP=A EBP
(ii) AD=BE
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Answer:
∠ EPA = ∠ DPB (Given)
⇒ ∠ EPA + ∠DPE = ∠ DPB + ∠DPE
∴ ∠APD = ∠BPE
Consider Δ’s DAP and EBP
AP = BP (Given P is midpoint of AB)
∠BAD = ∠ABE (Given)
∠APD = ∠BPE (Proved)
Hence ΔDAP ≅ ΔEBP (By ASA congruence rule) ⇒ AD = BE (CPCT)
Step-by-step explanation:
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