Math, asked by prabirbosekolkata, 4 months ago

AB is a line segment and PM is the perpendiculat bisector .Show that P is equi-distant from A and B

Answers

Answered by Anonymous

1

Step-by-step explanation:

since , AB is a line segment, L is drawn perpendicular to AB, A point 'p' lies on line L. : P is equidistant from A and B

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