AB is a line segment. AX and YB are two equal line segments drawn on opposite sides of AB such that AX || YB. If AB and XY intersect at M, Prove that AB and XY bisect each other at M
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i.e. AM=MB and XM=MY
angle AMX= YMB (vertically opp.angle)
angle AXM=MYB (alt. int. angle) where AX || BY.
XA=BY [GIVEN].
Therefore, AM=BM and XM=YM (BY C.P.C.T)
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fulform of C.P.C.T is Corresponding Part Of congruent Triangle.
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