AB is a line segment PB perpendicular AB and QAis perpendicular to AB are such That PO=5cm and QO=8 CM. if ar(triangPOB)=250 CM then find area of triangle QOA
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In figure ab is a straight line on which pb and ap sides are standing.
So,
in triangle aop and bop
op is a bisector of angle apb and ab line.
then, angle apo=bpo (op is the bisector of angle apb)
ao =ob (op is perpendicular and bisector of ab)
and, angle aop =bop=90 degree (op perpendicular ab making right angle )
Or,op =op (common )
then triangle aop congruent to triangles bop.
hence proved that op is that bisector and parpendicular of AB.
soyabbhatta87:
wrong answer
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