Question

Ab is a mirror arc in a circle with centre p. R is point on the major arc except a and b if angel APB= 150 then

Answer 1

Answer:

∠BAP=75

∘

∠OAP=90

∘

∴∠OAB=90

∘

−75

∘

=15

∘

So, ∠AOB=180

∘

−2(15

∘

)=150

∘

∴Exterior∠AOB=360

∘

−150

∘

=210

∘

So, ∠ACB=

2

1

(210

∘

)=105

∘

[Angle subtended by an arc at the centre is double than the angle subtended by it at the remaining part of the circle]

Answer 2

Answer:

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Step-by-step explanation:

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