Question

AB is a radius of a circle with centre O. C is a point on the circle. If ZOBC = 60° then fin
value of LOCA​

Answer 1

Step-by-step explanation:

AB is diameter and c is point

then triangle ACB form in semi-circle

angle ACB is 90 (angle in semi-circle)

By angle sum property

ACB + ABC + BAC = 180

90 + ABC + 45=180

ABC=180-135

ABC=45

In triangle OCB,

OC=0B (radius of circle)

OBC=OCB (angles opposite to equal sides)

OBC=OCB=45

OCB=45