AB is a tangent drawn to a circle with centre O write the measures of angle OPA
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Given- PQ is a tangent to a circle with centre O at Q. QOR is a diameter of the given circle so that ∠POR=120°
. To find out- ∠OPQ=?
Solution- QOR is a diameter.
∴OQ is a radius through the point of contact Q of the tangent PQ. ∴∠OQP=90°
since the radius through the point of contact of a tangent to a circle is perpendicular to the tangent.∴∠OPQ+∠OQP=120°
(external angles of a triangle=sum of the internal opposite angles )
∴∠OPQ=120°
−90°
=30°
.
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