Question

AB is a tangent drawn to a circle with centre O write the measures of angle OPA​

Answer 1

Answer:

Given- PQ is a tangent to a circle with centre O at Q. QOR is a diameter of the given circle so that ∠POR=120°

. To find out- ∠OPQ=?

Solution- QOR is a diameter.

∴OQ is a radius through the point of contact Q of the tangent PQ. ∴∠OQP=90°

since the radius through the point of contact of a tangent to a circle is perpendicular to the tangent.∴∠OPQ+∠OQP=120°

(external angles of a triangle=sum of the internal opposite angles )

∴∠OPQ=120°

−90°

=30°

.