Question

AB is a triangle right angled at c if Ab=25 cm and ac=7cm find bc​

Answer 1

BC will be 24 cm

${ab}^{2} = \: {ac}^{2} + {bc}^{2} \\ {bc}^{2} = {ab}^{2} - {ac}^{2} \\ {bc}^{2} = {25}^{2} - {7}^{2} \\ {bc}^{2} = 625 - 49 \\ bc = \sqrt{576} \\ bc = 24cm$

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Answer 2

Answer:

$ABC$ is a right angle triangle at $C$ or $AB$ is hypotenuse

$Or,$ using Pythagoras theorem,

$\sqrt{AB^{2}-AC^{2}} = BC$

$Or, BC= \sqrt{25^{2}-7^{2}} = \sqrt{625-49}=\sqrt{576} = \sqrt{24^{2}} = 24$

Or, $BC=24$.

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Step-by-step explanation: