AB is a uniform rod of mass M and length 2 metre. the ratio of tension in string I and string II if the rod is horizontal and in equilibrium is
1)2:5
2) 5:2
3)1:5
4)5:1
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Answer:
answer will be 3rd
just make two equations of rotational equilibrium using torque as r×f.
using proper sign you will get T1/T2=1/5
Hope it may help
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