Question

AB is a vertical pole with B at the ground level and A at the top. A man finds that the angle of elevation of the point A from a certain point C on the ground is 60°. He moves away from the pole along the line BC to a point D such that CD =7 m. From D the angle of elevation of the point A is 45°. Then the height of the pole is
(a) $\frac{7\sqrt{3}}{2}\frac{1}{\sqrt{3}-1}m$(b) $\frac{7\sqrt{3}}{2}(\sqrt{3}+1})m$
(c) $\frac{7\sqrt{3}}{2}(\sqrt{3}-1})m$(d) $\frac{7\sqrt{3}}{2}\frac{1}{\sqrt{3}+1}m$

Answer 1

Hello mate ☺

Option B is correct one

Hope it helps u...❤

Answer 2

AB is a vertical pole with B at the ground level and A at the top. A man finds that the angle of elevation of the point A from a certain point C on the ground is 60°. He moves away from the pole along the line BC to a point D such that CD =7 m. From D the angle of elevation of the point A is 45°. Then the height of the pole is

(a) $\frac{7\sqrt{3}}{2}\frac{1}{\sqrt{3}-1}m$

(b) $\frac{7\sqrt{3}}{2}(\sqrt{3}+1})m$

(c) $\frac{7\sqrt{3}}{2}(\sqrt{3}-1})m$✔

(d) $\frac{7\sqrt{3}}{2}\frac{1}{\sqrt{3}+1}m$