ab is chord of circle abc find cosa from the figure
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Here is the answer =>
Step-by-step explanation:
As AB is the diameter, so ΔABC lies in the semicircle. So angle C=90°(As angle in a semicircle is always 90°).
Therefore AB is the hypotenuse of ΔABC.
Pythagoras Theorem=>
h^2=b^2+a^2
AB^2=3^2+2^2
=9+4
=13cm
So AB=√13cm.
So CosA=B/H
=2/√13
So CosA is 2/√13 which is the required answer.
HOPE IT HELPS.
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