Question

AB is equal to ACin triangle ABC . if angle A is equal to 50 degree , find angleB and angle C

Answer 1

Given: Angle A = 50°, AB= AC

In ∆ ABC

Angle A + Angle B + Angle C =180°

(A.S.P. of a ∆)

=> angle B + angle c = 180° -50°

Since angle A = 50°

=> angle B + angle C = 130°

Now, AB = AC

Therefore, angle B = angle C

Since, opposite angles of equal sides are equal.

Therefore,

Angle B = Angle C = 130/2

=>Angle B = 65°

=>Angle C = 65°

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