Question

ab is line segment and line l is its perpendicular bisector.if a point p lies on l . show that p is equidistant from a and b.

Answer 1

very easy to prove when you consider line to be a chord of a circle

Answer 2

We have show ∆API congruent to ∆BPI

ok now

IP=IP....... common side

Angle PIA=Angle PIB ....both 90°

AI=BI...........PI is bisector

Therefore ∆API congruent to ∆BPI

now AP=BP......CPCT

Hence proved P is equidastant from A and B.