Question

AB is parallel to CD and EF is parallel to DQthen find angle PDQ angleAED and angle DEF​

Answer 1

Step-by-step explanation:

• Angle CDP = angle AED ( corresponding angle) So angle AED = 34 Now. angle AED + Angle DEF + Angle FEB = 180 ( Angles on straight line) 34 + Angle DEF + 78 =180 ( Angle AED = 34 is proved above and Angle FED =78 given) Angle DEF + 112=180. Angle DEF = 180 -112. Angle DEF = 68. So Angle DEF = 68. Angle DEF = Angle PDQ ( corresponding angle) so Angle PDQ = 68.