AB is parallel to CD angleBPQ=140 degrees and angle QRD =150bdegrees find angle PQR
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Step-by-step explanation:
now ,
draw a line parallel to ab and cd at point q
because of this the angle q is divided into 2 angles
mark the line as EF
here abllef ; pq is transversal.
at point p linear pair is formed
140+X=180
X=40°
q1= 40°( alternate angles)
now
efllcd; qr is transversal
at point r linear pair is formed
X+150=180
X=30°
q2 = 30°(alternate angles)
angle pqr= q1 +q2
= 40+30
=70°
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