AB is parallel to DC. AD is parallel to BC.∠ CDB = 72°.∠ CAB = 31°.Work out x, explaining each stage of your working in the comment box.
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AB is parallel to CD and BD is transversal,
∠D = ∠B [alt. int. ∠s]
∴∠B = 72°
AB is parallel to CD and CA is transversal
∠A = ∠C [alt. int. ∠s]
∴∠C = 31°
Putting centre point as O,
In ΔAOB
∠A + ∠B + ∠O = 180° [ASP of Δs]
31 + 72 + ∠O = 180
∠O = 180 - 103
∠O = 77°
∠x and ∠O form linear pair
∴∠x + ∠O = 180°
∠x = 180 - 77
∠x = 103°
∴ x = 103°
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