ab is parallel to dc and ad is parallel to then find angle dac
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angle ADC=40 ,BAC=50
angle B+angle D=180
(sum of opposite angles. of a quadrilateral
angle 50 +angle D=180
angle D=180-50
angle D=130
now in ∆ABC
angle BAC.+ angle ABC +angle ACB =180
50+130+angle ABC =180
180+angle ABC =180
angle ABC=180-180
angle ABC =0
therefore AD||BC
now in ∆ ADC
60 + 130 +angle DCA=180
angle DCA=180-170=10
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