Question

AB IS TANGENT TO A CIRCLE WITH CENTRE P TOUCHING THE CIRCLE AT B.
PA INTERSECTS THE CIRCLE AT M.
IF AB=35CM AND AM=25 CM
FIND DIAMETER OF THE CIRCLE

Answer 1

Given:

Given:ab is tangent to a circle with center P touching the circle at B. PA intersects the circle at M. if AB=35cm and AM=25cm,

Given:ab is tangent to a circle with center P touching the circle at B. PA intersects the circle at M. if AB=35cm and AM=25cm, To find:

Given:ab is tangent to a circle with center P touching the circle at B. PA intersects the circle at M. if AB=35cm and AM=25cm, To find:Find the diameter

Given:ab is tangent to a circle with center P touching the circle at B. PA intersects the circle at M. if AB=35cm and AM=25cm, To find:Find the diameterSolution:

Given:ab is tangent to a circle with center P touching the circle at B. PA intersects the circle at M. if AB=35cm and AM=25cm, To find:Find the diameterSolution:AB = 35cm, AM = 25 cm, let r be the radius of the circle,

Given:ab is tangent to a circle with center P touching the circle at B. PA intersects the circle at M. if AB=35cm and AM=25cm, To find:Find the diameterSolution:AB = 35cm, AM = 25 cm, let r be the radius of the circle, AP^{2} = AB^{2} + BP^{2}AP

Given:ab is tangent to a circle with center P touching the circle at B. PA intersects the circle at M. if AB=35cm and AM=25cm, To find:Find the diameterSolution:AB = 35cm, AM = 25 cm, let r be the radius of the circle, AP^{2} = AB^{2} + BP^{2}AP 2

Given:ab is tangent to a circle with center P touching the circle at B. PA intersects the circle at M. if AB=35cm and AM=25cm, To find:Find the diameterSolution:AB = 35cm, AM = 25 cm, let r be the radius of the circle, AP^{2} = AB^{2} + BP^{2}AP 2 =A

2

2 +BP

2 +BP 2

2 +BP 2

2 +BP 2 (25 + r)^{2} = 35^{2} + r^{2}(25+r)

2 +BP 2 (25 + r)^{2} = 35^{2} + r^{2}(25+r) 2

2 +BP 2 (25 + r)^{2} = 35^{2} + r^{2}(25+r) 2 =35

2 +BP 2 (25 + r)^{2} = 35^{2} + r^{2}(25+r) 2 =35 2

2 +BP 2 (25 + r)^{2} = 35^{2} + r^{2}(25+r) 2 =35 2 +r

2 +BP 2 (25 + r)^{2} = 35^{2} + r^{2}(25+r) 2 =35 2 +r 2

2 +BP 2 (25 + r)^{2} = 35^{2} + r^{2}(25+r) 2 =35 2 +r 2

2 +BP 2 (25 + r)^{2} = 35^{2} + r^{2}(25+r) 2 =35 2 +r 2 Simplifying the equation, we get r = 12 cm

2 +BP 2 (25 + r)^{2} = 35^{2} + r^{2}(25+r) 2 =35 2 +r 2 Simplifying the equation, we get r = 12 cmDiameter = 12 \times× 2 = 24 cm

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