AB is tangent to O. If AO=48 and BC=100, what is AB? The diagram is not drawn to scale.
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Answer:
140
Step-by-step explanation:
sol
seg AO=seg CO =48 ( radius of same circle)
BO=BC+CO (B-C-O)
BO=100+48
BO=148
In ∆ BAO is a right angle triangle
A= 90°
BO²= BA²+AO² (By pythagoras theorem)
148²=AB²+48²
21904= AB²+ 2304
AB²=21904-2304
AB²=19600
Taking square root on both side
AB= 140
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