Question

Ab is the chord of a circle with radius 10cm.tangents at a and b meet at a point p.find pa

Answer 1

heyaa

here is your answer

OA =10 cm
ON is perpendicular AB

AN=NB=16/2 = 8cm

according to pythagoras theorem,

in the triangle ONA,

ON² + NA² =OA²
ON² = OA² - NA²
ON² = 10² - 8²
ON = 6cm

tan ∠AON = an/on = 8/6= 4/3

tan∠AON = PA/OA
4/3 = PA/10
PA = 40/3 cm

hope it helps

Answer 2

Step-by-step explanation:

hey there