AB is the chord of the circle with centre O. If its radius OC intersects AB at M, OA= 10 cm, AB = 12cm, then MC = ______
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Answer:
Answer
OA is the radius of the circle
Perpendicular drawn from centre to a chord bisects the chord.
Therefore AM=
2
1
AB
AM=10cm
Thus, triangle OMA is right angled triangled at ∠OMA.
∠OMA=90
∘
.
By Pythagoras theorem,
OA
2
=OM
2
+MA
2
OA=
OM
2
+MA
2
OA=
(2
11
)
2
+10
2
OA=
144
cm
OA=12cm
Radius of a circle is 12cm.
Option B will be the answer.
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