Question

 AB is the diameter of a circle with center O and AT is a tangent. If ∠AOQ = 58°, find ∠ATQ.

Answer 1

angle ABQ = 1/2 angle AOQ= 1/2 * 58 = 29°we know angle A = 90So,∠BAT+ATQ = 180∠ATQ= 180- 90+29= 180- 119 = 61<br>therefore ΔATQ = 61