Math, asked by aanshi0604p524kh, 11 months ago

AB is the diameter of a circle with Centre O and CD parallel to AB. If angle DAB= 25°, then find the measure of the angle CAD

Answers

Answered by knjroopa
49

Answer:

40

Step-by-step explanation:

Given AB is the diameter of a circle with Centre O and CD parallel to AB. If angle DAB= 25°, then to find the measure of the angle CAD

AB is the diameter of the circle. We can take angle ADB = 90 degree since it is a semi circle.

It is given angle DAB = 25 = angle CDA (because alternate angles)

We get ABCD as a cyclic quadrilateral if all lines are drawn.

Now angle CDB = angle CDA + angle ADB = 25 + 90 = 115 degree

angle CAB + angle CDB = 180 (cyclic quadrilateral)

angle CAB + 115 = 180

    CAB = 180 - 115 = 65 degree

DAB + CAD = CAB

25 + CAD = 65

CAD = 65 - 25

CAD = 40 degree.

The measure of the angle CAD is 40 degree.

Answered by swarajdas54
2

Answer:

40

Step-by-step explanation:

Given AB is the diameter of a circle with Centre O and CD parallel to AB. If angle DAB= 25°, then to find the measure of the angle CAD

AB is the diameter of the circle. We can take angle ADB = 90 degree since it is a semi circle.

It is given angle DAB = 25 = angle CDA (because alternate angles)

We get ABCD as a cyclic quadrilateral if all lines are drawn.

Now angle CDB = angle CDA + angle ADB = 25 + 90 = 115 degree

angle CAB + angle CDB = 180 (cyclic quadrilateral)

angle CAB + 115 = 180

   CAB = 180 - 115 = 65 degree

DAB + CAD = CAB

25 + CAD = 65

CAD = 65 - 25

CAD = 40 degree.

The measure of the angle CAD is 40 degree.

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