Question

AB is the diameter of a semicircle of radius 4cm and ACB is the angle on the semicircle .If BC=2root7, find the length of AC?​

Answer 1

AC=6cm

AB Square =BC square + AC square, because angle ACB=90

Answer 2

Answer:

6 cm

Step-by-step explanation:

GIVEN: ACB is the angle on the semicircle

<ACB= 90

In ΔACB $AB^{2} =AC^{2} +BC^{2}$

              AC= $\sqrt{AB^{2} -BC^{2}$

                    =√$8^{2}-(2\sqrt{7})^{2}$

                     =√36

                    = 6