AB is the diameter of the circle with center C. PQ parallel to AB, AB=50cm, PQ =14cm. find BQ
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Answer:
Draw CM perpendicular PQ
PQ = 14cm,
∴ MQ = 7 cm, CN = 7;
CB = 25 cm
CQ = 25 cm
NB = 25 – 7 = 18
CM =
√
25
2
−
7
2
=
√
625
−
49
252−72=625−49
=
√
576
576 = 24
∴ NQ = 24
BQ =
√
N
Q
2
−
N
B
2
=
√
24
2
+
18
2
NQ2−NB2=242+182
=
√
576
+
524
=
√
900
576+524=900 = 30 cm
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