Question

AB is the diameter of the circle with centre O if angle PBQ = 25° angle PAB = 55° angle ARB = 50° find angle PBA angle BPQ and angle BAR​

Answer 1

Answer:

∠PBA=35°, ∠BPQ=100°, ∠BAR=40°

Step-by-step explanation:

Given AB is a diameter of a circle with centre O. If ∠PAB=55 ,∠PBQ= 25 and ∠ABR=50. We have to find the ∠PBA, ∠BPQ, ∠BAR

Now, ∠APB=∠ARB=90°   (∵angles in the semicircle)

In ΔAPB, By angle sum property of triangle

∠BAP+∠APB+∠PBA=180°

⇒ 55°+90°+∠PBA=180°

⇒ ∠PBA=35°

Now, ∠PQB=∠PAB=55°    (∵Angle subtended by the same chord)

In ΔPQB, By angle sum property of triangle

∠BPQ+∠PQB+∠QBP=180°

⇒ ∠BPQ+55°+25°=180°

⇒ ∠BPQ=100°

In ΔARB, By angle sum property of triangle

∠ARB+∠ABR+∠BAR=180°

⇒ 90°+50°+∠BAR=180°

⇒ ∠BAR=40°