Question

AB is the diameter of the larger semicircle.is equal to 21 CM, AM equal to MN equal to NB. semi circles are drawn with AM, MN and NB.calculate the area of shaded region

Answer 1

[FIGURE IS IN THE ATTACHMENT]
Area of semicircle with diameter( AB)= 21cm.
Radius of semicircle AB = 21/2 cm
Diameter AM= MN= NB (GIVEN)
AB = AM+MN+NB
AB = AM+AM+AM
AB = 3AM
21 = 3AM
AM= 21/3= 7 cm
AM= MN= NB= 7cm
Area of Semicircle of diameter AB=πr²/2
=[ (22/7)× 21/2×21/2]/2
= 693/4 cm²
Area of semicircle with diameter AM= area of semicircle diameter MN= Area of semi circle with diameter NB
Radius of semicircle with diameter AM,MN,NB= 7/2
Area of semicircle with diameter AM,MN,NB=πr²/2
= [(22/7)×7/2×7/2]/2
= 77/4 cm²
Area of shaded region = Area of semicircle with diameter AB - (Area of semicircle with diameter MN) +(Area of semicircle with diameter AM+Area of semicircle with diameter NB)
= 693/4 -(77/4) +(77/4 +77/4)= 693/4+77/4= 770/4= 192.5 cm²
Hence, the area of the shaded region is 192.5 cm²

HOPE THIS WILL HELP YOU...

Answer 2

Answer:

Step-by-step explanation is below

Hope you can understand...